Hello!
First, let's write the problem.
[tex]9\le \:17-4x[/tex]
We are going to switch sides in order to have the x on the left side.
[tex]17-4x\ge \:9[/tex]
Subtract 17 from both sides.
[tex]17-4x-17\ge \:9-17[/tex]
[tex]-4x\ge \:-8[/tex]
We have two options, divide both sides by -4, or multiply both sides by -1 in order to reverse the inequality. Let's try the second option.
[tex]\left(-4x\right)\left(-1\right)\le\left(-8\right)\left(-1\right)[/tex]
[tex]4x\le \:8[/tex]
Divide both sides by 4.
[tex]\frac{4x}{4}\le \frac{8}{4}[/tex]
Our final answer would be,
[tex]x\le \:2[/tex]
You can feel free to let me know if you have any questions regarding this!
Thanks!
- TetraFish
