Answer:
a. Maximum 3 baskets
b. Number of oranges = 6
c. Number of bananas = 4
d. Number of pears = 9
Step-by-step explanation:
Peter has 18 oranges, 27 pears and 12 bananas.
He wants to prepare the fruit baskets with the same number of each fruit in each basket.
a). Greatest number of fruit baskets can be prepared by calculating highest common factor.
Factors of 18 = 2×3×3
Factors of 27 = 3×3×3
Factors of 12 = 2×2×3
Now highest common factor of 18, 12 and 27 = 3
Therefore, maximum 3 baskets can be prepared.
b. Number of oranges in each basket = [tex]\frac{18}{3}=6[/tex]
c. Number of bananas in each basket = [tex]\frac{12}{3}=4[/tex]
d. Pears in each basket = [tex]\frac{27}{3}=9[/tex]
