Respuesta :
Answer:
[tex]\frac{2}{3}[/tex] is the Slope of a line that is perpendicular to a given line equation -2y=3x+7
Step-by-step explanation:
We are given here with the equation of the line [tex]-2y=3x+7[/tex] or we can write this equation as [tex]y=\frac{-3}{2}x+\frac{-7}{2}[/tex]
the general equation of the line [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept.
Compare the given equation with general equation we get,
the value of slope(m) [tex]=\frac{-3}{2}[/tex]
The slope of line perpendicular to a line is, [tex]m_{perpendicular}=\frac{-1}{m}[/tex]
Since, the slope of the given line is, m=[tex]\frac{-3}{2}[/tex]
then, [tex]m_{perpendicular}=\frac{-1}{\frac{-3}{2} }[/tex][tex]=\frac{2}{3}[/tex]
Therefore, the slope of a line that is perpendicular to a line whose equation is -2y=3x+7 is, [tex]\frac{2}{3}[/tex]
The slope of the line that is perpendicular to a line whose equation is -2y = 3x + 7 is 2/3.
For lines to be perpendicular to each other, the product of there slopes is equals to negative 1. This can be mathematically represented as follows
m₁ × m₂ = -1
where
m₁ and m₂ are slopes of the lines.
Therefore,
let's find the slope of the equation given
-2y = 3x + 7
divide both sides by -2
y = -3/2 x + 7/2
Using the slope equation model,
y = mx + c
where
m = slope
The slope in our equation will be - 3/2.
Using the first formula for perpendicular lines,
m₁ × m₂ = -1
-3/2 m₁= -1
m₁ = -2/-3
m₁ = 2/3
The slope of the line is 2/3
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