Respuesta :
Answer:
3 months
Step-by-step explanation:
Let after m months they saved same amount of money.
Given,
Saving of Jaclyn = $ 120,
Amount earned by him/her per month = $ 40,
So, the total amount contained by him/her in m months = Saving + earning for m months
= 120 + 40m,
Similarly, saving of Pedro = $ 180,
Amount earned by him/her per month = $ 20,
So, the total amount contained by him/her in m months = 180 + 20m
Thus, we can write,
120 + 40m = 180 + 20m
40m = 180 + 20m - 120
40m - 20m = 60
20m = 60
⇒ m = [tex]\frac{60}{20}[/tex] = 3.
Hence, it will take 3 months before which Jaclyn and Pedro have saved the same amount of money.
Linear equations can be solved by applying arithmetic operations separately for variables and constants. If they both save their entire allowances, 3 months will it take before Jaclyn and Pedro have saved the same amount of money
Let us assumed that the saving of Jaclyn and Pedro will be the same after n months.
Now, from the given data.
Saving of Jaclyn = $ 120
Amount earned by Jaclyn per month = $ 40
Total amount in hand of Jaclyn after work for n months will be the addition of current saving and the amount earned by Jaclyn after n months.
Thus,
[tex]\rm{Amount \;after \;n \;months}= 120 + 40n[/tex],
Similarly, the saving of Pedro = $ 180
Amount earned by Pedro per month = $ 20
Total amount in hand of Pedro after work for n months will be the addition of current saving and the amount earned by Pedro after n months.
Thus,
[tex]\rm{Amount \;after \;n \;months}= 180 + 20n[/tex]
According to the question,
[tex]\begin{aligned}&120 + 40n = 180 + 20n\\&40n = 180 + 20n - 120\\&40n - 20n = 60\\&20n = 60\\&n=\dfrac{60}{20}\\&n=3\end{aligned}[/tex]
Hence, If they both save their entire allowances, 3 months will it take before Jaclyn and Pedro have saved the same amount of money.
To know more about it, please refer to the link:
https://brainly.com/question/22375335
