What is the factored form of 6x2 + 11x – 10? (2x + )( x – )

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Respuesta :

rejkjavik rejkjavik · Answer 1 · 2019-01-08T16:13:32+01:00

Answer:

[tex]6x^2+11x-10=(2x+5)(3x-2)[/tex]

Step-by-step explanation:

we are given

[tex]6x^2+11x-10[/tex]

We can factor it

[tex]6x^2+11x-10=6x^2+15x-4x-10[/tex]

we can use grouping method

[tex]6x^2+11x-10=(6x^2+15x)-(4x+10)[/tex]

now, we can take out common terms

[tex]6x^2+11x-10=3x(2x+5)-2(2x+5)[/tex]

we can take 2x+5 from both terms

[tex]6x^2+11x-10=(2x+5)(3x-2)[/tex]

so, we get factor terms as

[tex]6x^2+11x-10=(2x+5)(3x-2)[/tex]

akposevictor akposevictor · Answer 2 · 2022-02-07T13:41:10+01:00

The factored form of 6x² + 11x - 10 is: (2x + 5)(3x - 2)

Given the algebraic expression, 6x² + 11x - 10, it can be factorized as shown in the steps below:

6x² + 11x - 10

6x² + 15x - 4x - 10

(6x² + 15x) - (4x - 10)

3x(2x + 5) - 2(2x + 5)

6x² + 11x - 10 = (2x + 5)(3x - 2)

Therefore, the factored form of 6x² + 11x - 10 is: (2x + 5)(3x - 2).

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