What value is added to both sides of the equation x^2 − 8x = −10 in order to solve by completing the square?
−8
16
−4
4

Respuesta :

x^2-8x=-10
we need to get (x-a)^2 with x^2-8x to figure it out
using (x-4)^2=x^2-8x+16 we see to add 16
x^2-8x=-10
x^2-8x+16=6
(x-4)^2=6
x-4=sqrt6
x=4+sqrt6 to solve for x
Let's solve your equation step-by-step.x28x=−10Step 1: Subtract -10 from both sides.x28x(−10)=−10(−10)x28x+10=0Step 2: Use quadratic formula with a=1, b=-8, c=10.x=−b±b24ac2ax=(−8)±(−8)24(1)(10)2(1)x=8±242x=4+6 or x=4−6Answer:x=4+6 or x=4−6