Respuesta :
Answer: 164.52 grams
Explanation:
According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given atoms}}{\text{Avogadro's number}}=\frac{3.09\times 10^{24}}{6.023\times 10^{23}}=5.13moles[/tex]
Mass of 1 mole of sulphur is = 32.07 g/mol
Thus mass of 5.13 moles of sulphur is =[tex]\frac{32.07}{1}\times 5.13=164.52g[/tex]
Thus mass of sulphur is 164.52 grams.
The mass of [tex]{\text{3}}{\text{.09}} \times {\text{1}}{{\text{0}}^{{\text{24}}}}[/tex] atoms of sulfur is [tex]\boxed{{\text{164}}{\text{.528 g}}}[/tex].
Further explanation:
Avogadro law:
According to Avogadro law, one mole of any substance contains [tex]{\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}[/tex] particles. These particles can be atoms or molecules.
Firstly the number of moles of sulfur is to be calculated. This is done by using equation (1).
The formula to calculate the moles of sulfur is as follows:
[tex]{\text{Number of moles of S}} = \frac{{{\text{Number of atoms of S}}}}{{{\text{Avogadro's Number}}}}[/tex] …… (1)
The number of atoms of S is [tex]{\text{3}}{\text{.09}} \times {\text{1}}{{\text{0}}^{{\text{24}}}}[/tex].
The value of Avogadro’s number is [tex]{\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ atoms}}[/tex].
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Number of moles of S}}&{\mathbf{=}}\left( {{\text{3}}{\text{.09}} \times {\text{1}}{{\text{0}}^{{\text{24}}}}{\text{ atoms}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ atoms}}}}}\right) \\&={\text{5}}{\text{.1311}}\;{\text{mol}}\\\end{aligned}[/tex]
Now the moles calculated from equation (1) are used to evaluate the mass of sulfur. This is done by using equation (2).
The formula to calculate the mass of sulfur is as follows:
[tex]{\text{Mass of S}} = \left( {{\text{Moles of S}}} \right)\left( {{\text{Molar mass of S}}} \right)[/tex] …… (2)
The moles of sodium are 5.1311 mol.
The molar mass of S is 32.065 g/mol.
Substitute 5.1311 mol for the moles of S and 32.065 g/mol for the molar mass of S in equation (2).
[tex]\begin{aligned}{\text{Mass of S}}&=\left({{\text{5}}{\text{.1311 mol}}}\right)\left({\frac{{{\text{32}}{\text{.065 g}}}}{{{\text{1 mol}}}}}\right)\\&=164.52{\text{8 g}}\\\end{aligned}[/tex]
Therefore the mass of sulfur is 164.528 g.
Learn more:
1. How many moles of Cl are present in 8 moles of [tex]{\text{CC}}{{\text{l}}_4}[/tex]? https://brainly.com/question/3064603
2. Calculate the moles of ions in HCl solution: https://brainly.com/question/5950133
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole concept
Keywords: sulfur, mass, atoms, Avogadro’s law, 164.528 g, 32.065 g/mol, S, molar mass of S, moles of S, 5.1311 mol, moles.
