Answer:
Option A is correct
[tex]x+20 \leq x^2+9[/tex]
Step-by-step explanation:
Let the number be x.
As per the statement:
The sum of a number and 20 is no more than the sum of the square of the number and 9.
"sum of a number and 20" translated to x + 20
"no more than" means [tex]\leq[/tex]
"sum of the square of the number and 9" translated to [tex]x^2+9[/tex]
then;
[tex]x+20 \leq x^2+9[/tex]
Therefore, the following inequalities can be used to determine this unknown number is, [tex]x+20 \leq x^2+9[/tex]
