Answer:
[tex]\frac{1}{12}[/tex]
Step-by-step explanation:
Let S be the sample space, when two fair six-sided number cubes are rolled.
The sample space is in attached pic.
Let E be the event when sum of the values is less than 4.
[tex]E=\left \{ (1,1), (1,2), (2,1) \right \}[/tex]
We know that [tex]P(E)=\frac{n(E)}{n(S)}[/tex] i.e [tex]P(E)=\frac{number\:of\:elements\:in\:E}{number\:of\:elements\:in\:S}[/tex]
So, [tex]P(E)=\frac{3}{36}=\frac{1}{12}[/tex]
