Answer-
[tex]\boxed{\boxed{y-6=2(x-5)}}[/tex]
Solution-
The two points on the line are (5, 6), (3, 2)
The slope of the line joining these two points is,
[tex]=\dfrac{y_2-y_1}{x_2-x_1}[/tex]
Here,
x₁ = 5
y₁ = 6
x₂ = 3
y₂ = 2
Putting the values,
[tex]=\dfrac{2-6}{3-5}[/tex]
[tex]=\dfrac{-4}{-2}[/tex]
[tex]=2[/tex]
The general point-slope formula is,
[tex]\Rightarrow y-y_1=m(x-x_1)[/tex]
m = slope = 2
x₁ = 5 and y₁ = 6
So,
[tex]\Rightarrow y-6=2(x-5)[/tex]
Therefore, the point slope form equation for line AB is [tex]y-6=2(x-5)[/tex]
