Answer: [tex]\frac{3}{3}[/tex] Or 1
Step-By-Step Explanation:
[tex]\left[\begin{array}{ccc}Sine&\frac{SinA}{A}\\Rule&\frac{SinB}{B}\\&\frac{SinC}{C} \end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}Cos&\frac{CosA}{A}\\Rule&\frac{CosB}{B}\\&\frac{CosC}{C} \end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}\frac{CosA}{SinA}=\frac{CosB}{SinB}=\frac{CosC}{SinC} \end{array}\right][/tex]
[tex]\left[\begin{array}{ccc}CosA&=\frac{3}{4.24}\\CosB&=\frac{3}{4.24}\end{array}\right][/tex]
Additional Answers:
Area: T = 4.5
Perimeter: p = 10.24
Semiperimeter: s = 5.12
Angle ∠ A = α = 89.929° = 89°55'43″ = 1.57 rad
Angle ∠ B = β = 45.036° = 45°2'8″ = 0.786 rad
Angle ∠ C = γ = 45.036° = 45°2'8″ = 0.786 rad
Height: ha = 2.123
Height: hb = 3
Height: hc = 3
Median: ma = 2.123
Median: mb = 3.352
Median: mc = 3.352
Inradius: r = 0.879
Circumradius: R = 2.12
Vertex coordinates: A[3; 0] B[0; 0] C[2.996; 3]
Centroid: CG[1.999; 1]
Coordinates of the circumscribed circle: U[1.5; 1.498]
Coordinates of the inscribed circle: I[2.12; 0.879]
Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 90.071° = 90°4'17″ = 1.57 rad
∠ B' = β' = 134.964° = 134°57'52″ = 0.786 rad
∠ C' = γ' = 134.964° = 134°57'52″ = 0.786 rad
