Answer : The chemical reaction between [tex] Ca(OH_{2})[/tex] and [tex] H_{2}SO_{4}[/tex] is is given below.
[tex] Ca(OH_{2})[/tex] + [tex] H_{2}SO_{4}[/tex] → [tex] CaSO_{4}[/tex] + [tex]H_{2}O[/tex]
When calcium hydroxide reacts with sulfuric acid it undergoes neutralization reaction. Which give salt of calcium sulfate and water as their products.
The complete ionic reaction will be like this
[tex] Ca^{2+}+ 2OH^{-} + 2H^{+} + SO_{4}^{2-} ----> CaSO_{4}_(s) + 2 H_{2}O_{(l)}[/tex]
And the net ionic equation will be as
[tex] 2OH^{-} + 2H^{+} ---> 2H_{2}O[/tex]
Taking into account the definition of net ionic equation, the net ionic equation is:
2 OH⁻ + 2 H⁺ → 2 H₂O
The net ionic equation is a chemical equation for a reaction that lists only the species that participate in the reaction.
In other words, an ionic equation is a chemical equation where electrolytes in aqueous solution are written as dissociated ions. Usually this is a salt dissolved in water.
On the other side, you should know that a spectator ion is an ion that appears both as a reactant and as a product in an ionic equation.
Spectator ions can be either cations (positively charged ions) or anions (negatively charged ions).
When writing a net ionic equation, spectator ions found in the original equation are ignored. Thus, the total ionic reaction is different from the net chemical reaction.
The balanced equation will be:
Ca(OH)₂+ H₂SO₄ → CaSO₄ + 2 H₂O
Taking into account that:
The total ionic equation in separated aqueous solution will be:
Ca²⁺ + 2 OH⁻ + 2 H⁺ + 2 SO₄²⁻ → Ca²⁺ + 2 SO₄²⁻ + 2 H₂O
In this case, Ca²⁺ and SO₄²⁻ are the spectator ions because they appear unchanged in both the product and the reagent. So these ions cancel out by writing the net ionic equation and you get:
2 OH⁻ + 2 H⁺ → 2 H₂O
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