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The combination of crumple zones and air bags and seat belts might increase the distance over which a person stops in a collision to as much as 1.00 m. what is the force exerted on a 65.0-kg driver who decelerates from 18.0 m/s to rest over a distance of 1.00 m?

Respuesta :

meerkat18
From Newton's second law of motion,

F = ma
We know m = 65 kg. Next, we have to find a through this formula:

v² = v₀² + 2ad
0² = (18 m/s)² + 2(a)(1 m)
Solving for a,
a = -162 m/s²

Thus,
F = (65 kg)(-162 m/s²) = -10,530 Newtons

Answer:

Newton 2 law

Explanation:

The sequence of speed-reducing technologies—crumple zone — seat belt — airbags — padded/deformable interior—are designed to work together as a system to reduce the peak force of the impact on the outside of the passenger(s)'s body by lengthening the time over which this force is imparted.

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