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What is the hydronium ion concentration and the ph for an aqueous solution of nh3 that has a hydroxide ion concentration of 2.25 × 10- 2 m?

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When ammonium is dissolved in wated, we have, NH3 + H2O >> NH4+ + OHÂŻ pOH = -log[OH-] pOH = -log[2.25x10^-2] pOH = 1.6478 Since pH + pOH=14. Therefore pH = 14 - pOH = 14 - 1.648 = 12.3522. [H+]=10^-pH [H+]=10^(-12.3522) [H+]= 4.3250 * 10 ^(-5)

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