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Bacteria in a pond multiplies as shown in the table. If a fungus on a tree decays at half that rate, what is the rate of decay (round to the nearest integer)?
thanks!

Bacteria in a pond multiplies as shown in the table If a fungus on a tree decays at half that rate what is the rate of decay round to the nearest integerthanks class=

Respuesta :

Kalahira
Using the formula, y=a(1=r)^x to solve for the growth rate and you find that the growth rate for the bacteria is 50%. Once this information is found, you can determine that a fungus decay at half that rate will be 25%.

Answer:

20%

Step-by-step explanation:

Population growth formula:

[tex]P = P_0 \times e^{rt} [/tex]

where P is the total population after time t,  [tex]P_0

[/tex]  is the starting population, r is the rate of growth and t is the time in hours

Solving for r:

[tex]\frac{ln(\frac{P}{P_0})}{t}=r[/tex]

and replacing with data:

P =  22.781

[tex]P_0[/tex] = 4.5 (taking hour 2 as initial time)

t = 4 hours (time elapsed between initial time and time the population reach P)

[tex]r=\frac{ln(\frac{22.781}{4.5)}{4}[/tex]

r = 0.4, that is equivalent to 40%

Then, fungus decay rate is 40%/2 = 20%

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