Exactly 500 grams of ice are melted at a temperature of 32°f. (lice = 333 j/g.) calculate the change in entropy (in j/k). (give your answer with three significant figures)

Respuesta :

Entropy Change is calculated  by (Energy transferred) / (Temperature in kelvin) 
deltaS = Q / T 

Q = (mass)(latent heat of fusion) 
Q = m(hfusion) 
Q = (500g)(333J/g) = 166,500J 

T(K) = 32 + 273.15 = 305.15K 
deltaS = 166,500J / 305.15K 
deltaS = 545.63 J/K