contestada

What is the inverse of the function f(x) =1\9 x + 2?

h(x) = 18x – 2
h(x) = 9x – 18
h(x) = 9x + 18
h(x) = 18x + 2

Respuesta :

WojtekR
[tex]f(x)=\dfrac{1}{9}x+2\\\\\\y=\dfrac{1}{9}x+2\\\\\\x=\dfrac{1}{9}y+2\\\\\\x-2=\dfrac{1}{9}y\quad|\cdot9\\\\\\y=9x-18\\\\\\\boxed{h(x)=9x-18}[/tex]

Answer B.

Answer:

B) h(x) = 9x  - 18

Step-by-step explanation:

f(x) = 1/9 x + 2

y= 1/9 x + 2

To find the inverse function follow the steps.

Step 1:

Replace x by y and y by x.

x = 1/9 y + 2

Step 2: Write y interms of x

1/9 y = x - 2

Multiplying both sides by 9, we get

9*1/9 y = 9x - 2*9

y = 9x -18

Therefore, answer is  B) h(x) = 9x  - 18

Hope this will helpful.

Thank you.

Otras preguntas