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If you have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, which element is the reactant in excess? 3H2 + N2 → 2NH3

Respuesta :

Answer:

nitrogen

Explanation:

The stoichiometry of the reaction says that [tex]H_{2}[/tex] and  [tex]N_{2}[/tex] react 3:1 to form 2 moles of  [tex]NH_{3}[/tex], so, if you have 3,5 moles of H, which is equal to 1,75 moles of  [tex]H_{2}[/tex], and 5 moles of N, which are equal to 2,5 moles of  [tex]n_{2}[/tex]. only[tex]\frac{1,75 moles of H2}{3}[/tex]=0.583 moles of  [tex]N_{2}[/tex], will react, leaving 1.917 moles of [tex]N_{2}[/tex] unreacted, and forming 0.583*2=1.166 moles of  [tex]NH_{3}[/tex]