A 5.0-kg mass with an initial velocity of 4.0 m/s, east collides with a 4.0-kg mass with an initial velocity of 3.0 m/s, west. after the collision the 5.0-kg mass has a velocity of 1.2 m/s, south. what is the magnitude of the velocity of the 4.0-kg mass after the collision?

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Answer:

A 5.0-kg mass with an initial velocity of 4.0 m/s, east collides with a 4.0-kg mass with an initial velocity of 3.0 m/s, west. after the collision the 5.0-kg mass has a velocity of 1.2 m/s, south. what is the magnitude of the velocity of the 4.0-kg mass after the collision?

The final velocity of the second mass after the collision is 0.5 m/s.

The given parameters:

  • Mass of the first particle, m₁ = 5.0 kg
  • Mass of the second object, m₂ = 4.0 kg
  • Initial velocity of the first object, u₁ = 4.0 m/s east
  • Initial velocity of the second object, u₂ = 3.0 m/s west
  • Final velocity of the first object, v₁ = 1.2 m/s

The total momentum of the two masses before collision is calculated as;

[tex]P_i = m_1 u_1 + m_2 u_2\\\\P_i = 5(4) + 4(-3)\\\\P_i = 20 - 12\\\\P_i = 8 \ kgm/s[/tex]

Apply the principle of conservation of momentum to determine the final velocity of the second object;

[tex]P_i = P_f\\\\m_1 v_1 + m_2 v_2 = P_f \\\\m_1v_1_y + m_2v_2_y = P_f\\\\5(1.2) + 4(v_2) = 8\\\\4v_2 = 8-6\\\\4v_2 = 2\\\\v_2 = \frac{2}{4} \\\\v_2 = 0.5 \ m/s[/tex]

Thus, the final velocity of the second mass after the collision is 0.5 m/s.

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