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When 8.21 l of c3h8 (g) burn in oxygen, how many liters of oxygen are consumed? all gas volumes are measured at the same temperature and pressure but not at stp?

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Kalahira
8.21 L of C3H8(g) Lets take c as the molar volume at that temperature.
    c L <><> 5c L
  C3H8 (g) + 5O2 (g) --> 3CO2 + 4H2O + Q
  8.21 L <><> x L
    x = (8.21 * 5c)/c = 8.21 * 5 = 41.05 L O2 consumed for a 100% yield.

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