Answer: 6.8 moles of oxygen are needed to completely react with 3.4 moles of [tex]CH_4[/tex]
Explanation:
[tex]CH_4+2O_2\rightarrow CO_2+2H_2O[/tex]
According to reaction, 1 mole of [tex]CH_4[/tex] is reacting with 2 moles of [tex]O_2[/tex] then, 3.4 moles of CH_4 will react with :
[tex]=\frac{2}{1}\times 3.4 \text{moles of }O_2 [/tex] = 6.8 moles of [tex]O_2[/tex]
Hence, 6.8 moles of oxygen are needed to completely react with 3.4 moles of [tex]CH_4[/tex].
