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ten plus eight times a number a equals eleven times another number d minus six solve for a

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TecciAmanda07
So your equation would be 8a+10=11d-6 First: you would combine like terms so normally you would take away the smaller number. So to cancel out the negative 6 you added you add positive six to the negative 6 so you would get 0 and whatever you do to one side you have to do to the other so you would do 10 + 6. Your new equation would be 8a+16=11d. Now you do -16 to both sides. So your new equation would be 8a= 11d - 16. Now you divide by 8. So your final equation would be a=11d-2.

Answer:

[tex]a=\frac{11d-16}{8}[/tex]

Step-by-step explanation:

We have been given a word phrase. We are asked to write an equation and solve for 'a'.

Eight times the number 'a' would be [tex]8a[/tex].

Ten plus eight times a number 'a' would be [tex]10+8a[/tex].

Eleven times another 'd' would be [tex]11d[/tex].

Eleven times another 'd' minus six would be [tex]11d-6[/tex].

Equate both expression:

[tex]10+8a=11d-6[/tex]

[tex]10-10+8a=11d-6-10[/tex]

[tex]8a=11d-16[/tex]

[tex]\frac{8a}{8}=\frac{11d-16}{8}[/tex]

[tex]a=\frac{11d-16}{8}[/tex]

Therefore, the value of 'a' is [tex]\frac{11d-16}{8}[/tex].

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