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darkdragonex
In order to figure this out you need to use slope intercept for for each of these hills. Let's say the first hill is HA and the second hill is B

slope intercept: y = mx + b

HA: y = (2/10)x
HB: y = (2/15)x

As you can see when you plot this on a graph, HB is steeper because the line rises more sharply.
facundo3141592

Answer: Ok, the first hill rises 2 feet for every 10 feet of run.

So if both hills start in the ground where y = 0, we can write the height as a function of x in the next way: y = (2/10)*X so for every 10 feet you advance in x, you rise 2 feet in Y, where here 2/10 is the slope.

The second hill is described by y = (2/15)*X, so for every 15 feet in x, you rise 2 feet in y, and the slope is 2/15

Is easy to see that 2/10 > 2/15, so the slope of the first hill is bigger than the slope of the second hill, this means that the first hill is steeper than the second.

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