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A 95 kg man lying on a surface of negligible friction shoves a 65 g stone away from himself, giving it a speed of 4.0 m/s. what speed does the man acquire as a result?

Respuesta :

carlosego
We can solve this problem by conserving linear momentum.
 We have then that:
 P1 = P2
 m1v1 + m2v2 = m1v1 '+ m2v2'
 Substituting values and clearing:
 95 (0) + 0.065 (0) = 95v + 0.065 (4)
 0 = 96v + 0.26
 96v = -0.26
 v = -0.0027 m / s
 The man moves in the opposite direction to the stone.
 answer:
 the speed that a man acquire as a result is v = -0.0027 m / s

W0lf93
Total momentum of the system must stay constant, so M1*V1 = -M2*V2. Substituting in the values and rearranging, we find -V2 = M1*V1 / M2. 65 grams = 0.065 kg, so
 0.065kg * 4.0m/s / 95kg = -2.7*10^-3 m/s. The negative indicates he is travelling in the opposite direction as the stone. Speed is independent of direction, so the final answer is 2.7*10^-3 m/s.

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