Write the balanced equation for the reaction of tin(iv) phospahte with sodium carbonate to make tin(iv) carbonate and sodium phosphate

Chemical reaction: Sn₃(PO₄)₄ + 6Na₂CO₃ → 3Sn(CO₃)₂ + 4Na₃PO₄.
Sn₃(PO₄)₄ - tin(IV) phosphate.
Na₂CO₃ - sodium carbonate.
Sn(CO₃)₂ - tin(IV) carbonate.
Na₃PO₄ - sodium phosphate.
Tin has oxidation number +4, sodium +1, carbonate has oxidation number -2 and phosphate anion has -3.

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dsdrajlin dsdrajlin · Answer 2 · 2020-04-15T02:26:32+02:00

Answer:

Sn₃(PO₄)₄ + 6 Na₂CO₃ ⇄ 4 Na₃PO₄ + 3 Sn(CO₃)₂

Explanation:

Let's consider the double displacement reaction of tin(IV) phosphate with sodium carbonate to make tin(IV) carbonate and sodium phosphate.

Sn₃(PO₄)₄ + Na₂CO₃ ⇄ Na₃PO₄ + Sn(CO₃)₂

We start balancing the elements that are just in one compound in each side, that is, Sn, P, Na and C. From these, we start with the one with the higher atomicity (there are 4 atoms of P in the left side).

Sn₃(PO₄)₄ + Na₂CO₃ ⇄ 4 Na₃PO₄ + Sn(CO₃)₂

Now, we have to balance the sodium atoms.

Sn₃(PO₄)₄ + 6 Na₂CO₃ ⇄ 4 Na₃PO₄ + Sn(CO₃)₂

Then, we have to balance the carbon atoms.

Sn₃(PO₄)₄ + 6 Na₂CO₃ ⇄ 4 Na₃PO₄ + 3 Sn(CO₃)₂

We verify that the equation is balanced.