Answer:
The area of the dilated rectangle is equal to [tex]40\ ft^{2}[/tex]
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to scale factor squared
Let
z-----> the scale factor
x------> the area of the dilated rectangle
y------> the area of the original rectangle
[tex]z^{2}=\frac{x}{y}[/tex]
we have
[tex]z=8[/tex] ------> is an enlargement
[tex]y=(5/8)\ ft^{2}[/tex]
substitute and solve for x
[tex]8^{2}=\frac{x}{(5/8)}[/tex]
[tex]x=64*(5/8)=40\ ft^{2}[/tex]
