lalith
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The roots of $3x^2 - 4x + 15 = 0$ are the same as the roots of $x^2 + bx + c = 0,$ for some constants $b$ and $c.$ Find the ordered pair $(b,c).$

Respuesta :

its is (c/x,1/2)
 Because math works this way the answer is write! yay

we are given

quadratic equation as

[tex] 3x^2-4x+15=0 [/tex]

now, we can find b and c from

[tex] x^2+bx+c=0 [/tex]

we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

[tex] 3x^2-4x+15=0 [/tex]

[tex] \frac{3x^2-4x+15}{3}= \frac{0}{3}  [/tex]

[tex] \frac{3x^2}{3}-\frac{4x}{3}+\frac{15}{3}= \frac{0}{3}  [/tex]

now, we can simplify it

[tex] x^2-\frac{4}{3}x+5= 0  [/tex]

now, we can compare it with

[tex] x^2+bx+c=0 [/tex]

we get

[tex] b=-\frac{4}{3} [/tex]

[tex] c=5 [/tex]

so, we get order pair as

[tex] (b,c)=(-\frac{4}{3} , 5) [/tex]..............Answer

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