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sbcardinals
9x^2 - 49y^2

(3x - 7y)(3x + 7y)
abidemiokin

The factor of 9x^2−49y^2 is (3x + 7y)(3x - 7y)

Difference of to square

According to the differnce of two square:

  • a^2-b^2 = (a+b)(a-b)

Given the expression 9x^2−49y^2

This can be further expressed as:

(3x)^2 - (7y)^2

Let a = 3x and b = 7y

Applying the rule, we will have:

9x^2−49y^2 = (3x + 7y)(3x - 7y)

Hence the factor of 9x^2−49y^2 is (3x + 7y)(3x - 7y)

Learn more on Difference of to square here: https://brainly.com/question/1123986

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