What is the area of this figure? Enter your answer in the box. units² An irregular heptagon is graphed on a coordinate plane. The horizontal x-axis ranges from negative 6 to 6 in increments of 1. The vertical y-axis ranges from negative 6 to 6 in increments of 1. The vertices of the heptagon are located at begin ordered pair negative 5 comma 3 end ordered pair, begin ordered pair negative 4 comma 5 end ordered pair, begin ordered pair negative 2 comma 3 end ordered pair, begin ordered pair 3 comma 4 end ordered pair, begin ordered pair 4 comma 3 end ordered pair, begin ordered pair 4 comma negative 3 end ordered pair, and begin ordered pair negative 3 comma negative 3 end ordered pair.

We divide the figure in the following areas:
Area of the two upper triangles:
Area of triangle 1:
At1 = (1/2) * (3) * (2) = 3
Area of triangle 2:
At2 = (1/2) * (6) * (1) = 3
Area of the complete lower rectangle
Ar = (9) * (6) = 54
Area of the lower triangle:
At3 = (1/2) * (2) * (6) = 6
The total area of the figure is:
At1 + At2 + Ar-At3 = (3) + (3) + (54) - (6) = 54
answer:
the area of this figure is 54 units^2

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ashishdwivedilVT ashishdwivedilVT · Answer 2 · 2022-03-03T15:10:40+01:00

area of the given heptagon is 54 square units.

what is heptagon?

It is a polygon having 7 sides.

coordinates of all 7 vertices are given as:

(-5,3)

(-4,5)

(-2,3)

(3,4)

(4,3)

(4,-3)

(-3,-3)

in the uploaded diagram. heptagon has been split into 5 triangles, called T1, T2, T3, T4, and T5.

Now the area of the heptagon= T1+T2+T3+T4+T5

AreaT1= 3*2/2=3

AreaT2= 3*6/2=9

AreaT5=6*7/2=21

AreaT3=14.5, Using the coordinate formula for the area of a triangle.

AreaT4=6.5, Using the coordinate formula for the area of a triangle.

Total Area= 3+9+21+14.5+6.5= 54

hence, the area of the given heptagon is 54 square units.

to get more about polygon refer to the link,

https://brainly.com/question/26215603