Respuesta :

Volume of a triangular pyramid=(1/3)Bh
B=base=area of the triangle located in the base=(1/2)(base)(height)=
=(9 cm)(15 cm)/2=67.5 cm²
height=32 cm

Volume=(1/3)/(67.5 cm²)(32 cm)=720 cm³

Answer: 720 cm³

Answer:

Option A is correct

720 [tex]\text{cm}^3[/tex] is the volume of the pyramid

Step-by-step explanation:

Volume of a triangular pyramids is given by:

[tex]V = \frac{1}{3}Bh[/tex]             ......[1]

where

V is the volume of the triangular pyramid

B is the base area

h is the height of the pyramids

From the given figure:

h = 32 cm

to find the Area of the base.

Use formula:

[tex]B = \frac{1}{2}xy[/tex]

where x represents the width and y represents the height of the Base in the pyramids.

Here, x = 9 cm and y = 15 cm

then;

[tex]B = \frac{1}{2}(9)(15)=\frac{135}{2}[/tex] centimeter square.

Substitute the value of B in [1] we get;

[tex]V = \frac{1}{3}\cdot \frac{135}{2} \cdot 32 = 45 \cdot 16[/tex]  

Simplify:

V = 720 centimeter cube

Therefore, the volume of the given pyramids is 720 [tex]\text{cm}^3[/tex]