Let, the amount of money grade 2 raised be $x.
Given, grade 4 raised $112 more than grade 2.
So the amount of money grade 4 raised = $([tex] x+112 [/tex]).
Also given, grade 3 raised $84 more than grade 4.
So the amount of money grade 3 raised = $([tex] x+112+84 [/tex]).
In the problem given, grade 3 raised $360.
We can write the equation as,
[tex] x+112+84 = 360 [/tex]
[tex] x+196 = 360 [/tex]
We can get x by moving 196 to the right side. As 196 is added there so we will subtract 196 from both sides to get x.
[tex] x+196-196 = 360-196 [/tex]
[tex] x = 360-196 [/tex]
[tex] x = 164 [/tex]
So we have got the required answer.
Grade 2 raised $164.
