Respuesta :

zrh2sfo
Solve the following system:
{y = x - 1 | (equation 1)
{2 x - y = 0 | (equation 2)

Express the system in standard form:
{-x + y = -1 | (equation 1)
{2 x - y = 0 | (equation 2)

Swap equation 1 with equation 2:
{2 x - y = 0 | (equation 1)
{-x + y = -1 | (equation 2)

Add 1/2 × (equation 1) to equation 2:
{2 x - y = 0 | (equation 1)
{0 x+y/2 = -1 | (equation 2)

Multiply equation 2 by 2:
{2 x - y = 0 | (equation 1)
{0 x+y = -2 | (equation 2)

Add equation 2 to equation 1:
{2 x+0 y = -2 | (equation 1)
{0 x+y = -2 | (equation 2)
Divide equation 1 by 2:
{x+0 y = -1 | (equation 1)
{0 x+y = -2 | (equation 2)
Collect results:
Answer:  {x = -1
                {y = -2
garydesir1
Hello there!

y = x - 1
2x - y = 0

We need to solve y = x - 1 for y

Start by substituting x - 1 for y in 2x - y = 0

2x - y = 0

2x - (x - 1)  = 0

2x - x + 1 = 0

x + 1 = 0

x = 0 - 1

x = -1

We can use the value of x to find the value for y

Substitute -1 for x in y = x - 1

y = x - 1

y = -1 - 1
y = -2

The answers are: x = -1 and y = -2


I hope you understand the steps and if you have any questions about the answer, just let me know.

As always, I am here to help you!

Otras preguntas