Respuesta :
pH of a solution is -ln[H3O+]
so,in case of A pH=3 or,-log[H3O+]=3 or,[H3O+]=10^-3
in case of B pH=6 pr,-log[H3O+]=6 or, [H3O+]=10^-6
so,hydronium ion concentration in solution A /the hydronium ion concentration in solution Z
=10^-3/10^-6
=1000
2)
Ca(OH)2+2 HNO3=Ca(NO3)2+2 H2O
so the answer is 2.
Answer: (4) 1000
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
[tex]pH=-\log [H^+][/tex]
[tex]pH=log\frac {1}{H^+}[/tex]
Thus as pH and [tex]H^+[/tex] are inversely related, a solution having lower pH will have more amount of [tex]H^+[/tex] concentration. And a solution having more pH will have less amount of [tex]H^+[/tex] concentration.
1. Solution A has a pH of 3
[tex]13=-log[H^+][/tex]
[tex][H^+_A]=10^{-13}[/tex]
2. solution Z has a pH of 6.
[tex]16=-log[H^+][/tex]
[tex][H^+_Z]=10^{-16}[/tex]
Thus Solution A with low pH has higher [tex]H^+[/tex] concentration.
[tex]\frac{H^+_A}{H^+_Z}=\frac{10^{-13}}{10^{-16}}=10^3=1000[/tex]
