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A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a
resistor. The circuit does not contain a voltmeter or an ammeter. When the circuit is operating, the
total current through the circuit is 0.50 ampere.
Determine the equivalent resistance of the circuit.

Respuesta :

     Considering the unknown resistence as R and using the Ohm's First Law, we have:

[tex]i= \frac{V}{R_{eq}} \\ 0.5= \frac{12}{R+10} \\ R+10=24 \\ R=14-Ohm[/tex]
 
     The equivalent resistence is given by the resistor series with the lamp resistence.

[tex]R_{eq}=R+10 \\ R_{eq}=14+10 \\ \boxed {R_{eq}=24-Ohm}[/tex]

If you notice any mistake in my english, please let me know, because i am not native.

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