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An electric dryer consumes 6.0 × 10^6 joules of
electrical energy when operating at 220 volts for
1.8 × 103 seconds. During operation, the dryer
draws a current of
(1) 10. A (3) 9.0 × 102 A
(2) 15 A (4) 3.3 × 103 A

Respuesta :

Answer : The dryer draws a current of 15 A.

Explanation :

Given that,

Energy consumed, [tex]E=6\times 10^6\ J[/tex]

Voltage, V = 220 Volts

Time, [tex]t=1.8\times 10^3\ s[/tex]

Power dissipated is given by :

[tex]P=\dfrac{E}{t}[/tex]

Also, P = VI

So, [tex]VI=\dfrac{E}{t}[/tex]

[tex]I=\dfrac{E}{Vt}[/tex]

[tex]I=\dfrac{6\times 10^6\ J}{220\ V\times 1.8\times 10^3\ s}[/tex]    

[tex]I=15\ A[/tex]

So, the correct option is (2)

Hence, this is the required solution.                                                  

The dryer draws a current of 15 A.Electric currents is the ratio of charge per unit of time.

What is electric current?

The pace at which electrons travel through a conductor is known as electric current. The ampere is the SI unit for electric current.

Electrons are tiny particles that reside within a substance's molecular structure.

The given data in the problem is;

V is the voltage= 220 volts

E is the electric energy= 6.0 × 10⁶

t is the time =1.8 × 10³ seconds.

I is the electric current=?

The electric current is found as;

[tex]\rm P= \frac{E}{t} \\\\\ P= VI \\\\ VI = \frac{E}{t} \\\\ I= \frac{E}{VT} \\\\ I= \frac{6 \times 101^6 }{220 \times 1.8 \times 10^3} \\\\ \rm I= 15 A[/tex]

Hence the dryer draws a current of 15 A.Electric currents is the ratio of charge per unit of time.

To learn more about the electric current refer to the link;

brainly.com/question/7643273

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