Respuesta :
Answer : Total energy dissipated is 10 J
Explanation :
It is given that,
Time. t = 10 s
Resistance of the resistors, R = 4-ohm
Current, I = 0.5 A
Power used is given by :
[tex]P=\dfrac{E}{t}[/tex]
Where
E is the energy dissipated.
So, E = P t.............(1)
Since, [tex]P=I^2R[/tex]
So equation (1) becomes :
[tex]E=I^2Rt[/tex]
[tex]E=(0.5\ A)^2\times 4\Omega \times 10\ s[/tex]
[tex]E=10\ J[/tex]
So, the correct option is (3)
Hence, this is the required solution.
Answer:
3) 10 J
Explanation:
Electrical energy dissipated is given as
[tex]U = i^2 R T[/tex]
here we know that
i = electrical current = 0.50 A
R = 4 ohm
T = 10 s
so we have electrical energy given as
[tex]U = (0.50)^2(4)(10)[/tex]
[tex]U = 10 J[/tex]
