Respuesta :
Energy = hc/λ, where h is planck's constant, c is the speed of light and λ is the wavelength.
Energy = （6.626 x 10^-34*3.00 x 10^8)/（4.80 × 10^−7）= 4.14*10^-19 J, which is 3.
Normally, when solving these equations, don't forget to check the units are correct (eg. wavelength is in meters) and dont forget to include the units in the calculation.
Energy = （6.626 x 10^-34*3.00 x 10^8)/（4.80 × 10^−7）= 4.14*10^-19 J, which is 3.
Normally, when solving these equations, don't forget to check the units are correct (eg. wavelength is in meters) and dont forget to include the units in the calculation.
Taking into account the definition of photon, energy of a photon, wavelength, frecuency and propagation speed, the correct answer is the option (3): The energy of a photon with aa wavelength of 4.80×10⁻⁷ meter is 4.14×10⁻¹⁹ J.
What is a photon and energy of a photon
You have to know that electromagnetic radiation carries energy, which can be absorbed or emitted. To explain the processes of emission and absorption, Plank and Einstein proposed that the energy of radiation is composed of indivisible units (quanta). In each elemental process only a quantum of light can be emitted or absorbed. Each of these quanta was called a "photon".
The exchanges of energy between matter and radiation take place not continuously, but by discrete and indivisible quantities or quanta of energy. The quantum of energy is proportional to the frequency of radiation.
The relationship between the amount of energy (E) transported by the photon and its frequency (f) is determined by the following expression, where the energy of a photon is obtained by multiplying Planck's constant h by the frequency f of electromagnetic radiation:
E=h×f
What is wavelength, frecuency and propagation speed
Wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).
On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f×λ
All electromagnetic waves propagate in a vacuum at a constant speed of 3×10⁸ m/s, the speed of light.
What is the energy of the photon in this case
In this case, you know:
- h= 6.63*10⁻³⁴ Js
- f= v÷λ where v= 3×10⁸ m/s and λ=4.80×10⁻⁷ m
Replacing in the definition of energy of a photon:
E=h× (v÷λ)
E= 6.63×10⁻³⁴ Js× (3×10⁸ m/s ÷4.80×10⁻⁷ m)
Solving:
E= 4.14×10⁻¹⁹ J
Finally, the correct answer is the option (3): The energy of a photon with aa wavelength of 4.80×10⁻⁷ meter is 4.14×10⁻¹⁹ J.
Learn more about
definition of photon and energy of a photon:
brainly.com/question/8924116
brainly.com/question/6945706
brainly.com/question/8000078
wavelength, frecuency and propagation speed:
brainly.com/question/8924116
brainly.com/question/6945706
brainly.com/question/8000078
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