Answer: 4) 40 ml
Solution :
According to the neutralization law,
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1[/tex] = molarity of NaOH solution = 0.30 M
[tex]V_1[/tex] = volume of NaOH solution = ?
[tex]M_2[/tex] = molarity of HCl solution = 0.80 M
[tex]V_2[/tex] = volume of HCl solution = 15 ml
Now put all the given values in the above law, we get the volume of NaOH solution.
[tex](0.30M)\times V_1=(0.80M)\times (15ml)[/tex]
[tex]V_1=40ml[/tex]
Therefore, the volume of 0.30 M NaOH required to neutralize 15 ml of 0.80 M HCl is 40 ml.
