Answer :
the first odd integer is x. The next odd integer will be x+2. and the next is x+4. Then we can say that (x)+(x+2)+(x+4)=87
working that out yields 3x+6=87
and thus 3x=81
and by consequence x=27
and thus our 3 odd integers are 27,29 and 31
working that out yields 3x+6=87
and thus 3x=81
and by consequence x=27
and thus our 3 odd integers are 27,29 and 31
Let be y - 2, y and y + 2 the 3 consecutives odd integers;
There sum is 3y, and, in the same time is 87 => y = 87/3 => y = 29 =>
y - 2 = 27; y + 2 = 31;
The 3 integers are : 27, 29, 31.
There sum is 3y, and, in the same time is 87 => y = 87/3 => y = 29 =>
y - 2 = 27; y + 2 = 31;
The 3 integers are : 27, 29, 31.
