Answer:
Greater.
Step-by-step explanation:
The in the function [tex]f(x)=2x^2+5\sqrt{x-2}[/tex], the square root term [tex]\sqrt{x-2}[/tex] has to give a real number if [tex]f(x)[/tex] is to be real. This can only happen if [tex]x\geq 2[/tex] because if [tex]x<2[/tex] then [tex]\sqrt{x-2}[/tex] will give a complex number and therefore [tex]f(x)[/tex] will not be real.
Thus, the domain for f(x) is all real numbers greater than or equal to 2.
