Respuesta :
Let's begin with moving the constant to the side with f(x):
f(x) - 7 = x² + 10x
Next let's add (half of 10)² to both sides of the equation: btw that is 25 but on the right side we will leave it as 5² because it will make the factoring easier
f(x) - 7 + 25 = x² + 10x + 5²
Lets simplify the left side a bit and factor the perfect square trinomial on the right.
f(x) + 18 = (x + 5)²
Finally move the constant back to the side with the binomial
f(x) = (x + 5)² - 18
The vertex is (-5, -18)
f(x) - 7 = x² + 10x
Next let's add (half of 10)² to both sides of the equation: btw that is 25 but on the right side we will leave it as 5² because it will make the factoring easier
f(x) - 7 + 25 = x² + 10x + 5²
Lets simplify the left side a bit and factor the perfect square trinomial on the right.
f(x) + 18 = (x + 5)²
Finally move the constant back to the side with the binomial
f(x) = (x + 5)² - 18
The vertex is (-5, -18)
Using the completing-the-square method the vertex form of the function
f(x) = x² + 10x + 7 is f(x) = (x + 5)² - 18
The given function is:
f(x) = x² + 10x + 7
Comparing f(x) = x² + 10x + 7 with f(x) = ax² + bx + c
a = 1, b = 10, c = 7
(b/2)² = (10/2)² = 5²
Add and subtract 5² to the right hand side of the equation
f(x) = x² + 10x + 5² + 7 - 5²
f(x) = x² + 10x + 5² + 7 - 25
f(x) = x² + 10x + 5² - 18
f(x) = (x + 5)² - 18
f(x) = (x + 5)² - 18 is of the form f(x) = a(x - h)² + k which is the vertex form of a quadratic equation
Therefore, the vertex form of the function f(x) = x² + 10x + 7 is
f(x) = (x + 5)² - 18
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