Answer: [tex]230^0C[/tex]
Explanation:
[tex]Q=m\times c\times \Delta T[/tex]
q = heat absorbed or released by a substance = 2000.0 J
m= Mass of substance = 10.0 g
c = specific heat of the substance = [tex]0.870 J/g^0C[/tex]
[tex]\Delta T=T_f-T_i[/tex] = Change in temperature
Putting in the values we get:
[tex]2000.0J=10.0g\times 0.870J/g^0C\times \Delta T[/tex]
[tex]\Delta T=230^0C[/tex]
Thus the temperature changed by [tex]230^0C[/tex].
