Answer:
x≤-6 or 0<x≤6.Option D.
Step-by-step explanation:
Given:
[tex]\frac{x}{4} \leq \frac{9}{x}.[/tex]
Subtract [tex]\frac{9}{x}[/tex] from both sides,
[tex]\frac{x}{4}-\frac{9}{x} \leq[/tex] 0
Simplifying by taking common denominator:
[tex]\frac{x^2-36}{4x}\leq[/tex]0
Factoring numerator:
[tex]\frac{(x+6)(x-6)}{4x}\leq[/tex]0
Computing the signs and selecting that one satisfies ≤ 0:
x≤ -6,0<x≤6.
Option D is the right answer.
