Respuesta :
Answer:
Frequency of [tex]d=2\sin (\frac{\pi t}{3})[/tex] is [tex]\frac{1}{6}[/tex].
Step-by-step explanation:
We have the harmonic equation as, [tex]d=2\sin (\frac{\pi t}{3})[/tex].
It is known that,
If a function f(x) has a period P, then the function cf(bx) has period [tex]\frac{P}{|b|}[/tex].
So, we have,
As the function [tex]\sin t[/tex] has [tex]2\pi[/tex], then [tex]d=2\sin (\frac{\pi t}{3})[/tex] will have period [tex]\frac{2\pi}{\frac{\pi}{3}}[/tex] = 6
Further, the frequency of a function is the reciprocal of its period.
Thus, the frequency of [tex]d=2\sin (\frac{\pi t}{3})[/tex] is [tex]\frac{1}{6}[/tex].
