Amare wants to ride a Ferris wheel that sits four meters above the ground and has a diameter of 50 meters. It takes six minutes to do three revolutions on the Ferris wheel. Complete the function, h(t), which models Amare's height above the ground, in meters, as a function of time, t, in minutes. Assume he enters the ride at the low point when t = 0.

Respuesta :

The distance from the bottom of the wheel to a point on the ground can be modeled by a sine function. h(t)=a*sin(kt)+b. b is the height of the wheel, or 4m. a is the radius of the wheel, 50/2=25m. 2pi/k is the 5sinof thw revolution, so 2pi/k=6/3=2, k=pi. h(t)=25sin(pi*t)+4. 

Answer:

The required function is [tex]y=-25\cos (\pi x)+29[/tex].

Step-by-step explanation:

The general form of a cosine function is

[tex]y=A\cos (Bx+C)+D[/tex]              .... (1)

where, A is amplitude, [tex]\frac{2\pi}{B}[/tex] is period, C is phase shift and D is mid line.

It is given that Ferris wheel that sits four meters above the ground and has a diameter of 50 meters. So the minimum value of the function is 4 and maximum value of the function 54 meters.

[tex]D=Midline=\frac{Maximum+Minimum}{2}=\frac{4+54}{2}=29[/tex]

It takes six minutes to do three revolutions on the Ferris wheel.

[tex]Period=\frac{6}{3}[/tex]

[tex]Period=2[/tex]

[tex]\frac{2\pi}{B}=2[/tex]

[tex]B=\pi[/tex]

Phase shift is not given so C=0.

Substitute B=π, C=0 and D=29 in equation (1).

[tex]y=A\cos (\pi x+0)+29[/tex]

[tex]y=A\cos (\pi x)+29[/tex]             ... (2)

He enters the ride at the low point when t = 0. It means the function passes through the point (0,4).

[tex]4=A\cos (\pi (0))+29[/tex]

[tex]4=A+29[/tex]

[tex]4-29=A[/tex]

[tex]-25=A[/tex]

The amplitude is -25. Put this value in equation (2).

[tex]y=-25\cos (\pi x)+29[/tex]

Therefore the required function is [tex]y=-25\cos (\pi x)+29[/tex].