a rock is thrown from the top of a tall building. the distance, in feet, between the rock and the ground x seconds after it is thrown is given by f(x)=-16x62-4x+382 How long after the rock is thrown does it hit the ground

Respuesta :

The first thing we are going to do in this case is to rewrite the function correctly.
 We have then:
 f (x) = - 16x ^ 2-4x + 382
 The moment the rock hits the ground we have f (x) = 0
 0 = -16x ^ 2-4x + 382
 We solve the polynomial looking for its roots which are:
 x1 = -5.012803699004288
 x2 = 4.762803699004288
 We ignore the negative root. The solution is:
 x = 4.76
 Answer: 
 it hits the ground 4.76 s after is thrown