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My teacher says everything is there to answer this question but I don't know. Someone please explain.

Two travellers spend from 12 o'clock to 6 o'clock walking along a level road, up a hill and back again. Their pace is 4 mph on the level, 3 mph uphill, and 6 mph downhill.

How far do they walk and at what time do they reach the top of the hill?

Respuesta :

musiclover10045
12 oclock to 6 oclock is 6 hours

d = distance
r = rate of speed

time to walk uphill : t1 = d/3
time to walk downhill: t2 = d/6
total distance = 2d ( up hill and down ill)
2d = (d/3 + d/6)r
2/(1/3 +1/6) = r
r = 4
average speed up and down the hill was 4 mph

total distance = (2/3 x 6 x 4) + (1/3 x 6 x 4)
total distance = 16 + 8 = 24 miles total

Average speed to top of hill = 2/(1/4 +1/3) = 3.43 mph

to top of hill = 24/2 = 12 miles

12 / 3.43 = 3.5 hours
12 oclock + 3.5 hours = 3:30

total miles was 24
arrived at top of hill at 3:30
ime to walk uphill : t1 = d/3
time to walk downhill: t2 = d/6
total distance = 2d ( up hill and down ill)
2d = (d/3 + d/6)r
2/(1/3 +1/6) = r
r = 4
average speed up and down the hill was 4 mph

total distance = (2/3 x 6 x 4) + (1/3 x 6 x 4)
total distance = 16 + 8 = 24 miles total

Average speed to top of hill = 2/(1/4 +1/3) = 3.43 mph

to top of hill = 24/2 = 12 miles

12 / 3.43 = 3.5 hours
12 oclock + 3.5 hours = 3:30

total miles was 24
arrived at top of hill at 3:30

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