hi friend,
[tex]the \: answer \: is \: 3 \: molar[/tex]
the solution is as follows
[tex]moles \: of \: NaCl \: in \: the \: solution[/tex]
=
[tex]give \: mass \: of \: sodium \: chloride \\ - - - - - - - - - - - - - - - - \\ molecular \: mass \: of \: sodium \: chloride \: [/tex]
=
[tex] \: \: 87.75 \\ - - - - \\ \: \: 58.44[/tex]
[tex] = \: 1.501 \: moles[/tex]
[tex] \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: moles \: of \: solute \\ Molarity \: = \: \: \: \: \: - - - - - - - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: volume \: of \: solution(litrs)[/tex]
[tex]applying \: the \: formulae \: [/tex]
converting ml to litres
1.501/(500/1000)
1.501 X 2
3 M
Hope it helps
