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A force of 15 N is applied to a spring, causing it to stretch 0.3 m. What is the spring constant for this particular spring?

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egenriether
Hooke's Law for springs is F=kx, where k is the spring constant, F is force and x is the displacement.  Here we have

[tex]15N=k0.3m \\ \\ \frac{15N}{0.3m}=k=50 \frac{N}{m} [/tex]

Note the units are Newtons per meter as we expect.  This is the same law regardless if we compress or stretch the spring.
50 N/M I just had this question and this is the answer to it.

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