Respuesta :
Answer:
Image distance, v = 22.5 cm
Height of the image, h' = 6.5 cm
Explanation:
It is given that,
Height of the object, h = 5 cm
Object distance, u = -18 cm
Focal length of the lens, f = +10 cm
Using mirror's formula :
[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}[/tex]
[tex]\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{(-18)}[/tex]
v = 22.5 cm
Magnification of the lens :
[tex]m=\dfrac{v}{u}=\dfrac{h'}{h}[/tex]
[tex]h'=\dfrac{v}{u}h[/tex]
[tex]h'=\dfrac{22.5\ cm}{-18\ cm}\times 5[/tex]
h' = -6.5 cm
Hence, this is the required solution.
